(x+2)(x-1)=x^2+5

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Solution for (x+2)(x-1)=x^2+5 equation:


Simplifying
(x + 2)(x + -1) = x2 + 5

Reorder the terms:
(2 + x)(x + -1) = x2 + 5

Reorder the terms:
(2 + x)(-1 + x) = x2 + 5

Multiply (2 + x) * (-1 + x)
(2(-1 + x) + x(-1 + x)) = x2 + 5
((-1 * 2 + x * 2) + x(-1 + x)) = x2 + 5
((-2 + 2x) + x(-1 + x)) = x2 + 5
(-2 + 2x + (-1 * x + x * x)) = x2 + 5
(-2 + 2x + (-1x + x2)) = x2 + 5

Combine like terms: 2x + -1x = 1x
(-2 + 1x + x2) = x2 + 5

Reorder the terms:
-2 + 1x + x2 = 5 + x2

Add '-1x2' to each side of the equation.
-2 + 1x + x2 + -1x2 = 5 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-2 + 1x + 0 = 5 + x2 + -1x2
-2 + 1x = 5 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-2 + 1x = 5 + 0
-2 + 1x = 5

Solving
-2 + 1x = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 1x = 5 + 2

Combine like terms: -2 + 2 = 0
0 + 1x = 5 + 2
1x = 5 + 2

Combine like terms: 5 + 2 = 7
1x = 7

Divide each side by '1'.
x = 7

Simplifying
x = 7

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